![]() Let’s assume “a” to be an array representing the spread of carry capacity over the four scavenges, where the sum of the 4 elements <= 1. This function can be summed four times, with a spread of the iCap (or capacity) for all different ratios. This gives the following formula for resources per hour: iCap * iRatio / ((Math.pow(Math.pow(iCap, 2) * 100 * Math.pow(iRatio, 2), 0.45) + 1800) * df) World information for duration_factor used to figure out the formula. By throwing the data of the duration_factor and game_speed into google sheets and letting sheets calculate a power trendline, I found that the formula is game_speed^(-0.55). This seems to be loosely based on the world speed. In this formula, df stands for the duration factor. The following equation is found for the duration of a scavenge: ((Math.pow(Math.pow(iCap, 2) * 100 * Math.pow(iRatio, 2), 0.45) + 1800) * df) Where iCap is the total capacity of all units, and iRatio is 10% for the first hunt, 25% for the second, 50% for the third and 75% for the fourth. ![]() In the game javascript the following formula can be found for how much a scavenge brings in: iCap * iRatio – The name of the world (start of the URL). In order for me to add a world, I need the following information: This calculator was approved on under ticket number T13900636. ![]()
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